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Ajax Error Status 200 Parsererror


Ensure that you have a line like below in WebApiConfig.Register. Method One You can either remove the dataType: 'json' property from the object literal... You also have to check the parameters you send. e.g: complete: function (xhr, status) { if (status === 'error' || !xhr.responseText) { handleError(); } else { var data = xhr.responseText; //... } } share|improve this answer edited Feb 22 '15 http://lanprolab.net/ajax-error/ajax-error-200-parsererror.php

If the parameter is TwitterId, then you have to pass an object to data, not a string: data: {TwitterId: row}. –Felix Kling May 31 '11 at 11:21 3 Does the What are the holes on the sides of a computer case frame for? Should I include him as author? What does a publishing company make in profit?

Ajax Error 200 Parsererror Jquery Validation Engine

in your url? –mccannf Feb 5 '13 at 17:40 Can you use Firebug or a similar tool (like Chrome or Safari's built in Developer Tool) to capture the actual The API works like a charm now :) I used the api client at first, but i want to stick with a jquery only approach. –Thomas Mar 21 '11 at 11:28 share|improve this answer answered Apr 12 '13 at 18:32 user2275545 411 add a comment| up vote 0 down vote I had a similar problem. I resolved it with a much easier way.

What are the most common misconceptions about Esperanto? hmmm, if i put the datatype to json it doenst work too. –Stack Stack Jul 10 '11 at 23:00 @Stack: It wouldn't do, unless the page you're calling it Since it is not returning a true form a json it will encounter a parser error. –David East Jul 16 '12 at 15:21 3 I'm having this issue in 1.9.1, Parser Error In Ajax Call To resolve the problem, I replaced it by a Boolean value for example.

Not the answer you're looking for? Ajax Error Parsererror Revolution Slider Make sure that your controller return something like: public JsonResult ActionName(){ //your code return Json(new { }); } share|improve this answer answered Jun 25 '15 at 14:53 Alexander Suleymanov 292 add I don't know if has to do anything with the DevExpress components that I'm using or not. All was resolved when I modified my server (node) to do response.writeHead(200, { "Content-Type": "application/json", "Access-Control-Allow-Origin": "http://localhost:8080" }); Literally cost me an hour of banging my head against the wall.

If you like my tutorials, consider make a donation to these charities.Popular PostsLoading...Comments Rising Posts (100k-500k pv)Loading...Rising Posts (10k-99k pv)Loading...Rising Posts (<10k pv)Loading...Favorites LinksAndroid Getting StartedGoogle App Engine - JavaSpring 2.5.x Jquery Ajax Parsererror Json today I try to refector my code and got this parsererror. jquery jsonp jquery-1.5 parse-error share|improve this question edited Mar 19 '11 at 1:10 asked Mar 19 '11 at 0:47 Thomas 3,20272545 add a comment| 9 Answers 9 active oldest votes up Somewhat obvious, but easy to forgot in the moment.

Ajax Error Parsererror Revolution Slider

I'd still suggest returning json as json rather than xml http://www.tentonaxe.com maxi326 Re: Re: 200 OK but parsererror? 6 years ago thank you for verifying that for me. get redirected here as I explained in my answer –Dario Rusignuolo Feb 28 '15 at 14:34 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Ajax Error 200 Parsererror Jquery Validation Engine the mobile website domain will (now api is a subdomain) be a different domain. Ajax Error Parsererror Syntaxerror Unexpected Token Hot Network Questions Donald Trump's Tax Return What happens to aircraft wreckage?

javascript jquery asp.net ajax json share|improve this question edited Dec 13 '14 at 15:58 Salman A 121k44257337 asked May 31 '11 at 11:17 Pankaj Mishra 7,756114991 2 Can you run Check This Out jQuery $ajax API I am running into a similar problem, and am unable to pull the JSON object from any callback functions. A professor has only proofread my paper. Your suggestion was the one that fixed it for me. Ajax Parser Error

In my case I wasnt returning anything but used a datatype by mistake. fish tank problem The shrink and his patient (Part 2) On the equality of derivatives of two functions. jQuery .ajax() Parser error Started by c2d1, Mar 24 2011 08:54 AM Please log in to reply No replies to this topic #1 c2d1 Posted 24 March 2011 - 09:20 AM Source Thanks! –Marcel Frehe Jan 28 '14 at 11:12 I have worked for 2 days trying EVERYONE's "solution" to this problem.

First of all, the webmethods in a webservice or page doesn't work for me, it always returns xml, in local works fine but in a service provider like godaddy it doesn't. Ajax Parsererror Jsonp share|improve this answer answered Jun 5 '14 at 16:00 William 22123 add a comment| up vote 0 down vote The same problem I was getting until I have not appended parameter from localhost) if (callback != null && callback.length() > 1) { writer.write(callback + "(" + jsonString + ");"); } else { writer.write(jsonString); } (The json object is an instance of JSONObject,

share|improve this answer answered Jul 10 '11 at 21:56 3nigma 25.3k44983 add a comment| up vote 0 down vote At last i have found the solution.

share|improve this answer answered Apr 4 '11 at 18:27 TheJediCowboy 2,1021672130 add a comment| up vote 1 down vote accepted I think you can find the answer to this question in Fixed the question –dkarzon Feb 21 '11 at 4:27 | show 3 more comments 11 Answers 11 active oldest votes up vote 145 down vote accepted I recently encountered this problem Can one be "taste blind" to the sweetness of stevia? Jquery Ajax Parsererror Unexpected Token Feeling stupid...

I am using no additional libraries to jQuery. In 'success' i have only success: function(res){ console.log(res);} share|improve this answer edited Oct 10 '12 at 20:30 Mike Two 25.5k66083 answered Jul 19 '12 at 9:06 pszemek 1 add a comment| Are we seeing everything slowly? have a peek here jquery webmethod share|improve this question asked Apr 15 '13 at 10:21 Daniel Ziga 2,20962153 What does the response look like? –David Hedlund Apr 15 '13 at 10:24 1

Train carriages in the Czech Republic Liquids in carry on, why and how much? I need help with negotiation A professor has only proofread my paper. Liquids in carry on, why and how much? Please re-enable javascript to access full functionality.

Should I include him as author? theory/application: how would someone begin translating a new language? I accepted a counter offer and regret it: can I go back and contact the previous company? http://jsonformatter.curiousconcept.com/ to validate it.

Not the answer you're looking for? I inspect my xmlrequest text and looks like this. [{"original":{"original":null,"MonitorId":"64ca8ce7-6b3b-4458-9d20-6cd731fc01d7","FullName":"TestName","ShortName":"Test","SortIndex":1,"OwnerUserId":"7c43898c-2fc0-474d-92d7-9c47ff3b822a","LatitudeWGS84":24.325,"LongitudeWGS84":120.7536,"Altitude":13.65,"IsDefaultMonitor":false,"MonitorGroupId":"f9645bf3-a961-480d-b17a-4fa6755fbfae","ShareOptionId":3,"IsDisabled":false,"LoggerId":"bb7b93f0-7d91-483a-871a-0529a5317929"}, "MonitorId":"64ca8ce7-6b3b-4458-9d20-6cd731fc01d7","FullName":"TestName","ShortName":"Test","SortIndex":1,"OwnerUserId":"7c43898c-2fc0-474d-92d7-9c47ff3b822a","LatitudeWGS84":24.325,"LongitudeWGS84":120.7536,"Altitude":13.65,"IsDefaultMonitor":false,"MonitorGroupId":"f9645bf3-a961-480d-b17a-4fa6755fbfae","ShareOptionId":3,"IsDisabled":false,"LoggerId":"bb7b93f0-7d91-483a-871a-0529a5317929"}] which looks just fine to me. or you can plug it into any of the other xml validators Edit2: http://validator.w3.org/checkshows your xml as valid, not sure what to look at after that, 200 response means the Browse other questions tagged javascript ajax jquery or ask your own question.

share|improve this answer answered May 21 at 12:47 Parveen Verma 2,963179 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign Do you see the JSON data you show in Firebug? –Pekka 웃 Feb 21 '11 at 1:12 No I dont have a live link. Was Gandalf "meant" to confront the Balrog? In it, you'll get: The week's top questions and answers Important community announcements Questions that need answers see an example newsletter By subscribing, you agree to the privacy policy and terms

Like : "http://de.dawanda.com/api/v1/" + resource + ".json&c=?" May solve your problem. Join them; it only takes a minute: Sign up parsererror after jQuery.ajax request with jsonp content type up vote 48 down vote favorite 10 I am using jQuery Version 1.5.1 to